use python

Q1.1: Hey Bruno, where is your Mars? Write a function name in order that takes a list of strings as an input and return a list that contains exactly the same elements as the original list, except that it is rearranged so that every word "Bruno" is immediately followed by a word "Mars". Do not move the "Bruno" item, but every other item may move. The list contains the same number of words "Bruno" and "Mars"s. Every word "Bruno" has an item after it that is not a "Bruno", and a "Bruno" appears in the list before any "Mars". Note: It is possible that sometimes your output will be different (for longer inputs). For example, another possible output for the third doc test might be: ['Rock, 'Bruno', 'Mars', 'Bruno', 'Mars', 'Scissors', 'Stars', 'Paper'] def namein order (names): " Return a list where each 'Bruno' is followed by 'Mars o>> name_in_orde: ("I","Bruno", "like", "Mars")) 'I', 'Bruno', Mars 'like >s name in_order (("Marina", "Langlois"]) 'Marina, 'Langlois' o name in orde: (("Rock", "3runo", "Stars", "Bruno", "Paper", "Mars", "Scissos", "Mars"]) 'Rock', 'Bruno, 'Mars', 'Bruno', 'Mars,'Stara, 'Scissors','Paper' # Your code goes here #