Use Python to calculate how many different passwords can be formed with $6$ lower case English letters $($excludes any character not found in the English alphabet$).$ For a $1$ letter password, there would be $26$ possibilities; one for every letter of the

English alphabet. For a $2$ letter password, each letter is independent of the other, so there would be $26$ times $26$ possibilities. Using this information, print the amount of possible passwords that can be formed with $3$ letters.

$1$ # Enter code here:

$2-$

$3$

$4$ # Should print $17576$

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