Question: Use Substitution to evaluate 0 1 ( 3 v 2 ( 1 + v 3 2 ) 2 ) d v A . Let u

Use Substitution to evaluate 01(3v2(1+v32)2)dv
A. Let u= therefore: du=dv
=>01(3v2(1+v32)2)dv=
B. FTC does not apply because function is not continuous at 0,1
Use Substitution to evaluate 01(3v2(1+v32)2)dv A. Let u= therefore: du=dv =>01(3v2(1+v32)2)dv=

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