Use the "Closed Interval Method" to find the Absolute Maximum and Absolute Minimum values of $f(x)=x-\sqrt[3]{x}$ in the closed interval $-1,3$;

Find all critical numbers of $f.$

Find the exact values of $f$ at the critical numbers of $f$ in $-1,3.$

Find the exact values of $f$ at the endpoints of the interval $-1,3.$

Find the exact absolute max and absolute min values of $f.$