Use the curved pool wall image below to answer the following questions. The depth of the pool wall is $1$ ft and

${}_{H_{2}O}=62\mathrm{.}4l\frac{b}{f}{t}^3$

The figure below is adapted from "Geometric properties of some common shapes".

$=ba$

$I_{xc}=\frac{1}{12}b{a}^3$

$I_{yc}=\frac{1}{12}a{b}^3$

$I_{xyc}=0$

$\frac{4}{3}$

$A=\frac{R^2}{4}$

$I_{xc}=I_{yc}=0\mathrm{.}05488R^4$

$I_{xyc}=-0\mathrm{.}01647R^4$

$($b$)$ Quarter circle

Note: keep one significant figure after decimal for values in the blanks.

The force $F_1$ that acts on surface $BC$ is

type your answer...

lb$.$

$F_1$ ac

ft to the right of point $B.$

The force $F_2$ that acts on projected surface BD is

lb$.$

The weight $W$ of the water contained within is

lb$.$

Wact

ft to the right of point.

The resultant force $F_R$ that the water exerts on the pool is

lb$.$