Use the data you collected in lab on the previous side to determine how you would make $1\mathrm{.}00L$ of the secondary dye that is the same color. The MW of the dyes are:

Red$-3($R$-3),$ erythrosine, $C_{20}{H}_6{I}_{4}N{a}_2{O}_5,$ MW $879\mathrm{.}86\frac{g}{m}ol.$

Blue$-1($B$-1),$ brilliant blue, $C_{37}{H}_{34}{N}_{2}N{a}_2{O}_9{S}_3,$ MW $792\mathrm{.}85\frac{g}{m}ol.$

Yellow$-5($Y$-5),$ tartrazine, $C_{16}{H}_9{N}_{4}N{a}_3{O}_9{S}_2,$ MW $534\mathrm{.}3\frac{g}{m}ol.$

In order to make more dye, you will need to start with solid materials. So$,$ you must calculate how many grams of the appropriate dyes you need.

Red Dye $=,\frac{g}{L}$

Blue Dye $=,\frac{g}{L}$