Question: Use the following values to construct a third Lagrange polynomial approximation to f(1.03) f(1.0)=0.1924f(1.05)=0.2414f(1.10)=0.2933f(1.15)=0.3492
Use the following values to construct a third Lagrange polynomial approximation to f(1.03) f(1.0)=0.1924f(1.05)=0.2414f(1.10)=0.2933f(1.15)=0.3492
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