Use the graphical method to construct the shear$-$force and bending$-$moment diagrams for the beam shown. Let $a=8\mathrm{.}0ft,b=6\mathrm{.}0ft,c=12\mathrm{.}0ft,d=4\mathrm{.}5ft,w_B=5\mathrm{.}0$kip$\frac{s}{f}t,$ and $w_{CE}=3\mathrm{.}0$kip$\frac{s}{f}t.$ Construct the shear$-$force and bending$-$moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.

Calculate the reaction forces $B_y$ and $D_y$ acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free$-$body diagram below. $($Note: Since $B_x=0,$ it has been omitted from the free$-$body diagram.$)$

Answers:

Determine the bending moment acting at each of the following locations:

$($a$)x=B\mathrm{.}0$ ft li$.$e$..$ at support $B)$

$($b$)x=14\mathrm{.}0ft($i$.$e$.$ at point $C)$

$($c$)x=26\mathrm{.}0ft$ li$.$e$..$ at support $D_i$

$($d$)x=30\mathrm{.}5ft($i$.$e$.$ at point $E)$

When entering your answers. use the bending$-$moment sign corvention detailed in Section $7\mathrm{.}2.$

Answers

$($a$)M=$ kip$-$ft

$($b$)M=1$ kip$-$ft

$($c$)M=11$ kip$-$ft

$($d$)M=$ kip$-$ft

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Hint

Assistance Used

To find the moment at support $B.$ it may be helpful to first write an expression for the distributed load as a function of $x$ on the interval from point $A$ to support $B.$ If this function is integrated twice with respect to $x$ on the interval from $A$ to $B.$ the result is the area underneath the shear$-$force diagram between A and $B.$ Note that the area underneath the shear$-$force diagram from point $A$ to support $B$ is negative because the distributed load acts dowrward.

Part $5$

Determine the bending moment acting at $x=$xco $($calculated in Part $3)$ where $V=0$ kips between support $B$ and point $C.$

Answer: $M=$

kip$-$ft

$"$ I need help with part $4$ and $5$