Use the Laplace transform to solve the given initial value problem. $$ \begin{array}{1} y^{\prime \prime}-6 y^{\prime}+58 y=\delta _{1}(t) \\\ y(0)=-1, \quad y^{\prime}(0)=25 \end{array} $$ Y(s)=\frac{e^(-s)+31-s}{s^{2}-6+58) $$ $$ $$ y(t)= $$