Use the Limit Comparison Test to determine convergence or divergence.

${\displaystyle \underset{n=1}{\overset{}{}}}\frac{0\mathrm{.}0013}{n+8}$

Select the expression below that could be used for $b_n$ in the Limit Comparison Test and fill in the value of the limit $L$ in your choice.

$b_n=\frac{1}{n}$ gives $L=$

$b_n=\frac{1}{n^2}$ gives $L=$

$b_n=n$ gives $L=$

$b_n=\sqrt[\phantom{2}]{n}$ gives $L=$