Use the rules for definite integration and the formulas to the right to evaluate the integral

Integral from $6$ to $0$ left parenthesis $9$ x squared plus x minus $2$ right parenthesis dx$609$x$2+$x$2$dx$.$

Integral from a to b cdx equals c left parenthesis b minus a right parenthesis for any constant c$$abcdx$=$c$($b$$a$)$for$$any$$constant$$c

Integral from a to b xdx equals StartFraction b squared Over $2$ EndFraction minus StartFraction a squared Over $2$ EndFraction for b greater than a$$abxdx$=$b$22$a$22$for$$b$>$a

Integral from a to b x squared dx equals StartFraction b cubed Over $3$ EndFraction minus StartFraction a cubed Over $3$ EndFraction for b greater than a nbsp$$abx$2$dx$=$b$33$a$33$for$$b$>$a$$

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Part $1$

Integral from $6$ to $0$ left parenthesis $9$ x squared plus x minus $2$ right parenthesis dx$609$x$2+$x$2$dxequals$=$enter your response here

$($Simplify your$$ answer.$)$