Use the thermochemical equation:

$xe{F}_2(g)+H_2(g)2HF(g)+xe(g),H=-430kJ$

Together with the average bond energies given below, to calculate the average bond energy of the $xe-F$ bond in $xe{F}_2(g)$

Bond Average Bond Energy $(k\frac{J}{m}ol)$

a$)+288\mathrm{.}0kJ$

b$)-288\mathrm{.}0kJ$

e$)+132\mathrm{.}5kJ$

d$)-350\mathrm{.}5kJ$

e$)+265\mathrm{.}6kJ$