Question: Using any method, prove the following identity for all n 1: n (2nk)2 2nk1 (n k) = 5n6 n1 . k=0 Hint: I suggest expanding
Using any method, prove the following identity for all n 1:
n (2nk)22nk1(n k) = 5n6n1.
k=0 Hint: I suggest expanding out (x+x2)n with the Binomial Theorem and taking a derivative, but that is probably not the only way.
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
