Question: Using any method, prove the following identity for all n 1: n (2nk)2 2nk1 (n k) = 5n6 n1 . k=0 Hint: I suggest expanding

Using any method, prove the following identity for all n 1:

n (2nk)22nk1(n k) = 5n6n1.

k=0 Hint: I suggest expanding out (x+x2)n with the Binomial Theorem and taking a derivative, but that is probably not the only way.

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