Using Java, write a method called eTaylor that takes as input (i.e. argument) a double x and returns the value of e^x. This method should NOT use any Math library functions, so you will need to use Taylor Series for ex (loop until terms become close to 0, say 10e-16): e^x = 1 + x + (x^2/!2) + ( x^3/!3) + (x^4/!4) + ... Hint: Write a helper method for finding the nth power of a number x, divided by n! = n(n1)(n2)...21 that is, your helper method should accept an x and output x^n/!n

**Note from professor: You should have two methods, eTaylor and eTaylorHelper. eTaylor iterates through values of n and keeps a sum of the values returned by eTaylorHelper. eTaylorHelper should take a value x and a value n, then return x^n/n! You should never be calling palindrome checker during eTaylor.