USING LOOP in C++

1 program to approximate the value of the transcendental number e, (which is also irrational) using the infinite series defined below k! 2 6 k=0 where k-k*(k-1) * (k-2) * * 3 * 2 * 1 5! = 5 * 4 * 3*2+1=120 01 = 1 (by definition.) For example: 6! = 6 * 5! = 6 * 5 * 4 * 3 * 2 * 1 = 720 +-+-+-+-+-= 1 + 1 + + 1/6 + 1/24 +1/120= 2.716667 Approximate the value of e to 18 terms in the infinite series above. You will need to evaluate the series to 18 terms as shown below: 18 = 1 + 1 +-+-+ k! +--2.718282 2! 3! 18! k=0 After 18 terms the approximation should be: 2.718282