Question: using newton raphson method how we get 1.443742 Example: Find a root of the function f(x)=sinxx3+1.25 with 103 accuracy. Solution: f(x)=cosx3x2 and let us take
Example: Find a root of the function f(x)=sinxx3+1.25 with 103 accuracy. Solution: f(x)=cosx3x2 and let us take p0=1. p1=p0f(p0)f(p0)=p0cosp03p02sinp0p03+1.25=1cos1312sin113+1.25p1=1.443742R.E=p1p1p0=1.4437421.4437421=0.307355>103
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