Question: Using Pumping Lemma one can show the language L = { | n N } is not regular. This is done by way of contradiction.

Using Pumping Lemma one can show the language L= {Using Pumping Lemma one can show the language L= { | n | n N } is not regular. This is done by way of contradiction. We assume L is regular. Since L is infinite, Pumping Lemma applies. We then consider the string N } is not regular. This is done by way of contradiction. where We assume L is regular. Since L is infinite, Pumping Lemma applies. is the number of states of the DFA that recognizes L. Since the length of We then consider the string where is the number of states of is bigger than the DFA that recognizes L. Since the length of is bigger than , by Pumping Lemma, there exists strings , by Pumping Lemma, there exists strings such that , , and such that for all . If then the first repeated state on the acceptance , path must be a final state. Why? , image text in transcribed and image text in transcribed for all image text in transcribed . If image text in transcribed then the first repeated state on the acceptance path must be a final state. Why?

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