Using separation of variables technique, solve the following differential equation with initial condition d and y(3) = 5. dy =1 yx+5x 2+1 The solution is: OA. In y + 5 = In (x+1) B. In |y + 5| = arctan3+]n10 arctan3 == C. y = In (x + 1) + 50 In 10 - D. y = In (x + 1) + 25 - In 10 - E. In | y + 5 = In (x + 1) + In(10)