Using Table $7\mathrm{.}11,$ calculate the weight of wet fine aggregate $($non$-$crushed stone$)$ to make a $15,000-$ Ib of non$-$air$-$entrained concrete mix with a nominal maximum aggregate size of $1$ in$.$ Choose the nearest answer.

TA B LE $7\mathrm{.}11$ Relative Components of Concrete for Small Jobs, by Weight"

$\backslash$table$[[\backslash$table$[[$Nominal$],[$Maximum$],[$Size of$],[$Coarse$],[$Aggregate$],[$mm $($in$.)]],$Air$-$Entrained Concrete,Non$-$Air$-$Entrained Concrete$],[$Cement$,\backslash$table$[[$Wet Fine$],[$Aggregate$]],\backslash$table$[[$Wet Coarse$],[$Aggregate$]],$Water,Cement,$\backslash$table$[[$Wet Fine$],[$Aggregate$]],\backslash$table$[[$Wot Coarse$],[$Aggregate$"*]],$Water$],[9\mathrm{.}5(\frac{3}{8}),0\mathrm{.}210,0\mathrm{.}384,0\mathrm{.}333,0\mathrm{.}073,0\mathrm{.}200,0\mathrm{.}407,0\mathrm{.}317,0\mathrm{.}076],[12\mathrm{.}5(\frac{1}{2}),0\mathrm{.}195,0\mathrm{.}333,0\mathrm{.}399,0\mathrm{.}073,0\mathrm{.}185,0\mathrm{.}363,0\mathrm{.}377,0\mathrm{.}075],[19(\frac{3}{4}),0\mathrm{.}176,0\mathrm{.}296,0\mathrm{.}458,0\mathrm{.}070,0\mathrm{.}170,0\mathrm{.}320,0\mathrm{.}442,0\mathrm{.}068],[25(1),0\mathrm{.}169,0\mathrm{.}275,0\mathrm{.}493,0\mathrm{.}063,0\mathrm{.}161,0\mathrm{.}302,0\mathrm{.}470,0\mathrm{.}067],[37\mathrm{.}5(1\frac{1}{2}),0\mathrm{.}159,0\mathrm{.}262,0\mathrm{.}517,0,062,0\mathrm{.}153,0\mathrm{.}287,0\mathrm{.}500,0\mathrm{.}060]]$

"Data obtained from Portland Cement Association, $2008.$

If crushed stone is used, dexrease coarse aggregate by $50kg$ and increase fine aggregate by $50kg$ for each cubic meter of concroto $($or decrease coarse aggregate by $3lb$ and incroase fine aggregate by $3lb$ for each cubic foot of concrete$).$

$4125lb$

$1885lb$

$3921lb$

$2715lb$

$4530$lb

$234$lb