Using the above data Solve the following:

Initial diameter ot specimen do $=5$mm

Initial gauge length of specimen Lo$=80$mm

Initial cross$-$section area of specimen AO$=$

Load of yield point Fy$=$

Load at fracture Ff$=$

Final length after specimen breaking Lf$=$

Dia. Of specimen at breaking place df$=$

Cross section area at breaking place Af$=$

Young's Modulus E$=(\backslash$Delta $\backslash$sigma $)/(\backslash$Delta $\backslash$epsi $)=(\backslash$sigma $1-\backslash$sigma $2)/(\backslash$epsi $1-\backslash$epsi $2)=(($P$1)/($AO$)-($P$2)/($AO$))/((\backslash$epsi $1)/($Lo$)-(\backslash$epsi $2)/($Lo$))=$

Stress at offset point: $\backslash$sigma $\_(0\mathrm{.}2)=($P$\_(0\mathrm{.}2))/($Ao$)=$

Tensile Strength: $\backslash$sigma $\_($t$)=($P$\_($t$))/($Ao$)=$

Fractures Stress: $\backslash$sigma $\_($f$)=($P$\_($f$))/($Ao$)=$

Fracture Toughness: $=(\backslash$sigma $\_($y$)+\backslash$sigma $\_($t$))/(2)\backslash$times $\backslash$epsi $\_($f$)=$

Toughness and Modulus of Toughness. U$\_($T$)=((\backslash$sigma $\_($y$)+\backslash$sigma $\_($u$))/(2))$e$\_($f$)$

Resilience and modulus of resilience. U$\_($R$)=(1)/(2)\backslash$sigma $\_($y$)$e$\_($y$)*(1)/(2)\backslash$sigma $\_($y$)((\backslash$sigma $\_($y$))/($E$))=((\backslash$sigma $\_($y$)^(2))/(2)$E$)$ A: Results of mild steel sample

$\backslash$begin$\{$tabular$\}\{|$cc$|\}$

$\backslash$hline Extension $($mm$)$ & Load $\backslash ((\backslash$mathrm$\{$N$\})\backslash )\backslash \backslash$

$\backslash$hline $0$ & $0\mathrm{.}90\backslash \backslash$

$\backslash$hline $0\mathrm{.}83$ & $4694\mathrm{.}34\backslash \backslash$

$\backslash$hline $1\mathrm{.}67$ & $4831\mathrm{.}41\backslash \backslash$

$\backslash$hline $2\mathrm{.}50$ & $4781\mathrm{.}08\backslash \backslash$

$\backslash$hline $3\mathrm{.}33$ & $4918\mathrm{.}83\backslash \backslash$

$\backslash$hline $4\mathrm{.}17$ & $4926\mathrm{.}58\backslash \backslash$

$\backslash$hline $5\mathrm{.}00$ & $5257\mathrm{.}07\backslash \backslash$

$\backslash$hline $5\mathrm{.}83$ & $5437\mathrm{.}01\backslash \backslash$

$\backslash$hline $6\mathrm{.}66$ & $5575\mathrm{.}88\backslash \backslash$

$\backslash$hline $6\mathrm{.}75$ & $5584\mathrm{.}21\backslash \backslash$

$\backslash$hline $6\mathrm{.}76$ & $5584\mathrm{.}04\backslash \backslash$

$\backslash$hline $6\mathrm{.}77$ & $5591\mathrm{.}60\backslash \backslash$

$\backslash$hline $6\mathrm{.}77$ & $5587\mathrm{.}98\backslash \backslash$

$\backslash$hline $8\mathrm{.}33$ & $5775\mathrm{.}18\backslash \backslash$

$\backslash$hline $9\mathrm{.}16$ & $5847\mathrm{.}52\backslash \backslash$

$\backslash$hline $10\mathrm{.}00$ & $5911\mathrm{.}04\backslash \backslash$

$\backslash$hline $10\mathrm{.}83$ & $5965\mathrm{.}41\backslash \backslash$

$\backslash$hline $11\mathrm{.}67$ & $6010\mathrm{.}53\backslash \backslash$

$\backslash$hline $12\mathrm{.}50$ & $6042\mathrm{.}57\backslash \backslash$

$\backslash$hline $13\mathrm{.}33$ & $6072\mathrm{.}26\backslash \backslash$

$\backslash$hline $14\mathrm{.}16$ & $6092\mathrm{.}93\backslash \backslash$

$\backslash$hline $15\mathrm{.}00$ & $6113\mathrm{.}24\backslash \backslash$

$\backslash$hline $15\mathrm{.}83$ & $6129\mathrm{.}65\backslash \backslash$

$\backslash$hline $16\mathrm{.}67$ & $6140\mathrm{.}36\backslash \backslash$

$\backslash$hline $17\mathrm{.}50$ & $6146\mathrm{.}37\backslash \backslash$

$\backslash$hline $18\mathrm{.}33$ & $6148\mathrm{.}14\backslash \backslash$

$\backslash$hline $19\mathrm{.}16$ & $6149\mathrm{.}17\backslash \backslash$

$\backslash$hline $20\mathrm{.}00$ & $6147\mathrm{.}15\backslash \backslash$

$\backslash$hline $26\mathrm{.}85\mathrm{.}85$ & $6142\mathrm{.}22\backslash \backslash$

$\backslash$hline $21\mathrm{.}66$ & $6130\mathrm{.}59\backslash \backslash$

$\backslash$hline $22\mathrm{.}50$ & $6120\mathrm{.}44\backslash \backslash$

$\backslash$hline $23\mathrm{.}33$ & $6099\mathrm{.}74\backslash \backslash$

$\backslash$hline $24\mathrm{.}16$ & $6050\mathrm{.}83\backslash \backslash$

$\backslash$hline $25\mathrm{.}00$ & $5940\mathrm{.}21\backslash \backslash$

$\backslash$hline & $5675\mathrm{.}33\backslash \backslash$

$\backslash$hline $25\mathrm{.}83$ & $-7\mathrm{.}95\backslash \backslash$

$\backslash$hline

$\backslash$end$\{$tabular$\}$