Question: Using the equations 2 Fe (s) + 3 Cl (g) 2 FeCl (s) H = -800.0 kJ/mol Si(s) + 2 Cl (g) SiCl (s) H

Using the equations 2 Fe (s) + 3 Cl (g) 2 FeCl (s) H = -800.0 kJ/mol Si(s) + 2 Cl (g) SiCl (s) H = -640.1 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction 3 SiCl (s) + 4 Fe (s) 4 FeCl (s) + 3 Si (s)

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