Using the instruction provided in the appendix, measure the electrical resistance of the heating element. If the cross section of the heating element looks like Figure $1,$calculate d$.$The electrical conductivity of the heating element which is made of nickel and chromium, also known as nichrome, is $210^6/$m$.($Hint: Length can be determined by dividing the measured volume by the area$)$

given:

Resistance $($R$)=0\mathrm{.}3$ k$=300$

Volume of heating element $($V$)=20$ mL $=2010$ m$^3$

Electrical conductivity of nichrome $=210/$m

Cross$-$sectional length $($L$)=6\mathrm{.}2$ cm $=0\mathrm{.}062$ m