using ubuntu linux clone

Q3. Environment variables and execve() In this task, we study how environment variables are affected when a new program is executed via execve(). The function execve() calls a system call to load a new command and execute it; this function never returns. No new process is created; instead, the calling process's text, data, bss, and stack are overwritten by that of the program loaded. Essentially, execve() runs the new program inside the calling process. We are interested in what happens to the environment variables, are they automatically inherited by the new program? Step 1. Please compile and run the following program, and describe your observation. This program simply execute a program called /usr/bin/env, which prints out the environment variables of the current process. #include #include extern char ** environ; int main() char *argv[21; argv[0] = "/usr/bin/env"; argv[1] = NULL: execve("/usr/bin/env", argv, NULL); return 0; Step 2. Now, change the invocation of execvel) to the following and describe your observation execve("/usr/bin/env", argv, environ); Step 3. Please draw your conclusion regarding how the new program gets its environment variables