Question: v18 SI. No. Random No. for inter arrival time Inter arrival time (Mins.) Entry Service time in start time queue as per as per clock

v18 SI. No. Random No. for inter arrival time Inter arrival time (Mins.) Entry Service time in start time queue as per as per clock clock Random no for service time Service time (Mins.) end time as per clock Waiting Idle time of time customer (Mins.) (Mins.) 1 78 8 8.08 8.08 44 6 8.14 8 2 26 4 8.12 8.14 21 4 8.18 2 94 10 8.22 8.22 73 8 8.30 4 4 08 2 8.24 8.30 96 10 8.40 6 5 46 4 8.28 8.40 63 6 8.46 12 6 63 8.34 8.46 35 6 8.52 12 NO N 18 8.36 8.52 57 6 8.58 16 8 35 4 8.40 8.58 31 6 9.04 18 9 59 6 8.46 9.04 84 8 9.12 18 10 12 2 8.48 9.12 24 4 9.16 34 11 97 10 8.58 9.16 05 4 9.20 18 12 82 8 9.06 9.20 37 6 9.26 14 140 12 Total Time Average time spent by the customer waiting in the queue = 140/12 = 11.67 minutes Probability of idle time of petrol station - Total Operating Total Idle time - 12/86 = 0.1395 time of the Service Channel * Service End Time - 9.26 Hrs. Service Channel opened at 8.00 hrs. i.e. Total Time of the Service Channel = 1 hr. 26 Mins = 86 Mins. Illustration 19. A retailer deals in a perishable commodity. The daily demand and supply are variables. The data for the past 500 days show the following demand and supply: Availability (kg.) Supply (No. of days) Demand (kg.) Demand (No. of days) 10 40 10 50 20 50 20 110 30 190 30 200 40 150 40 100 50 70 50 40 The retailer buys the commodity at 20 per kg. and sells at 30 per kg. Any commodity remains at the end of the day, has no sales value. Moreover the loss on unsatisfied demand is 28 per kg. Given the following pair of random numbers, simulate 6 days sales, demand and profit: (31. 18) (63.84) (15.79) (07.32) (43,75) (81.27). The first random number in the pair is that of supply and the second random number is for demand
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