Question: Verify that the solution of u = f(x), u(0) = 0, u(1) = 0 is given by u(x) = fk(x,y)f(y)dy where 1 k(x,y) =
Verify that the solution of u" = f(x), u(0) = 0, u(1) = 0 is given by u(x) = fk(x,y)f(y)dy where 1 k(x,y) = { 1 (0-1) 0x y 1.
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To verify that is a solution to the differential equation ux fx with boundary conditions u0 u1 0 we ... View full answer
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