Question: Vibrating String when varying frequency Length of the string: L= 1.56m (include units) Make sure you got the length of the string correctly in m.

Vibrating String when varying frequency

Length of the string: L=1.56m (include units)

Make sure you got the length of the string correctly in m.

Wavelength depends on the length of the string and it is the distance between two loops.

=2L/N, where N=number of loops

Linear density of the stringm=mass/unit length (kg/m) is a material property of the string and represents the mass per unit length To get that cut a piece of string from the spool, measure its mass and length and get the ratio of these two.

Data Table Mass of Hanger 50 grams for tension on string

mstandard= kg/m

L= 1.56m cm= 156 m 0.0011 grams
f(Hz) 1/f (s) N (# of loops)

=2L/N

(m)

75 0.013 9 0.346
37.5 0.026 4 0.78
40 0.025 5 0.624
57.5 0.017 7 0.445
65 0.015 8 0.39
32.5 0.030 4 0.78
50 0.02 6 0.52

  1. In Excel, make a scatter plot of wavelength. (m) on the y axis vs 1/f (s) on x axis.

Include a trendline with the trendline equation what is the slope?

Include units for slope:

Slope=

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