Question: W e have x n + 1 = x n - f ( x n ) f ' ( x n ) = x n

We have
xn+1=xn-
f(xn)
f'(xn)
=xn-
xn5-xn-4
5xn4-1
.
Therefore, we get the following. (Round your final answer to six decimal places.)
x2=2-
79
=

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