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In a full duplex communication by using UTP cable. Pt = 250 w, Pr = 23 w and NEXTdb = 11,67. According to this information which answer is correct? O a Pc - 23.00 Adb = 11,02 ACRdb = 0.66 O b. Pc = 17.00 Adb = 10.36 ACRdb = 1.31 O CPC = 9.42 Adb = 8.48 ACRdb = 3.20 O d. Pc = 20,00 Adb 11.02 ACRdb 0,66 O e. Pc = 20,00 Adb = 11,67 ACRdb = 0,00 For the above given signal each bit is separated by a vertical line. If duration of a bit is given as 12 ms, which answer is correct? a. Data: 111010001000 Modulation Rate: 2 MBaud Encoding: Manchester O b. Data: 100011100110 Modulation Rate: 0.17 MB aud Encoding: Differantial Manchester O cData 111101000 10 0 Modulation Rate:1 Kbps Encoding: Differantial Manchester O d. Data: 111101000100 Data Rate: 0.08 Kbps Encoding: Manchester O e. Data: 1 00011100110 Modulation Rate: 2 KBaud Encoding: Differantial Manchester In a communication, the transmitted data is 010011000110 and the received data is 010001110110. For error detection 2D Parity algorithm is used with (4 row and 3 column). Which answer is correct? a. Error can be detected and corrected O b. Error is detected by row and column, but cannot be corrected OcError is only detected by column, but cannot be corrected d. Error is only detected by row, but cannot be corrected e. Error cannot be detected In an asenkron transmission a character size is 8 bits. When 1700 characters are transmitted, if total amount of data transmitted is 18,7 Kbit which answer is correct? O a Stop Bit = 1 Parity = 'Odd Total Overhead = 6.30 Koit O b. Stop Bit = 1 Parity = 'Even Total Overhead = 4,80 Kbit O c Stop Bit = 1 Panity = 'Even Total Overhead = 5.40 Kbit O d. Stop Bit = 1 Parity = 'Odd" Total Overhead = 5,10 Kbit Oe. Stop Bit = 1,5 Parity = "Odd" Total Overhead = 4,90 Kbit Signal 12.14 1011 Sample The given signal is digitized by using PCM using 4 bits. Which one is the correct data? 110010101111101110101100 ob. 001101000101001110101011 O c000010100011010010101100 O d. 101000111011010111001111 O e. 001110101011010100001100