Water $($density $=1\mathrm{.}0{10}^{3}k\frac{g}{m^3})$ flows downhill through a pipe of diameter $3\mathrm{.}0$ cm $.$ Its speed at the top of the hill is $5\mathrm{.}7\frac{m}{s}.$ If the hill is $26$ m high, what is the gravitational potential energy density of the water at the top of the hill relative to the bottom?

$2\mathrm{.}6{10}^4\frac{J}{m^3}$

Cannot be calculated without knowing the pressure.

$8\mathrm{.}8{10}^5\frac{J}{m^3}$

$1\mathrm{.}6{10}^4\frac{J}{m^3}$

$2\mathrm{.}5{10}^5\frac{J}{m^3}$