Water flows at $\backslash (12\mathrm{.}8\backslash$mathrm$\{$~m$\}/\backslash$mathrm$\{$s$\}\backslash )$ in a horizontal pipe with a gauge pressure of $2\mathrm{.}23\backslash ($ x $10^\{\backslash$wedge$\}4\backslash$mathrm$\{$~Pa$\}\backslash ).$ If the pipe widens to twice its original radius, what is the gauge pressure $($in Pa $)$ of the water in the wider section? $($You may treat the water as incompressible in this case.$)$