D. More About Dimensional Analysis and Conversion Factors here are a number of ways to solve any word problems. In the previous example: There 525 px 0.000625 kg 1000 m 1000 This calculation required two conversion factors, one quotient for (mg and g) and another for (g and kg) based on the equalities (1000 mg Ig) and (1000 g- 1 kg). respectively. However, if one recognizes this equality (1 kg 1,000,000 mg), then the calculation can be done in a single step with one conversion factor: 525p0000525 kg-5.25 x 10 10% Notice the use of scientific notation which eliminates all place-holder zeros. Both approaches to the word problem are correct since both calculations render the same answer. With complex, multi-step problems, it is recommended to do all calculations in a step-wise fashion unless you know your conversion facts are correct. CTQ17 Write a grammatically correct definition of a place-holder zero. CTQ 18 Convert 2450 km into micrometers. For each calculation, complete each conversion factor and solve the equation b. 2459 km; 2459 km x CTQ 19 Write each answer above in scientific notation.