We are going back to the exact same problems from Homework $18$ and $20$ except we will now

consider shear connectors. Instead of a continuous hollow box, we have built the beam below

by nailing the two horizontal flanges $(10010mm)$ to the two vertical webs. Each web gets one

nail $($you only need to focus on the upper one, the bottom is identical$).$ If your nail spacing along

the length of the beam is $120mm,$ find the required nail strength $V_s.($Recall: $V=4kN,l=27\mathrm{.}79x$

${10}^{-6}{m}^4.$ You do not have to compute those again. Answer: $V_s=0\mathrm{.}82kN.$We are going back to the exact same problems from Homework $18$ except we will now consider shear stress. The distributed load has a value of q$=-2$k$($N$)/($m$)$ and the beam span length is $4$ meters. I re$-$did the distances you need in mm $.$ You do not have to draw the shear diagram. You can "remember" that the maximum shear force is q$($L$)/(2)$ at the left $($and right support$).$ So V$=4$ kN$.$ Use that. Recall that the centroid is halfway up $($at $10$cm $)$ and I$=27\mathrm{.}79\backslash$times $10^(-6)$m$^(4).$ You do not have to compute those again. Find the shear stress at three locations: a$)$ at the centroid, where it will be a maximum; b $)$ at the interface between the web and flange $($there are two webs in this problem$)$ but in the web; c$)$ at the interface but in the flange. $,$ all MPa$).$