Question: We define the loss variable L by L = EAD SEV L, where L = 1p with E[15] = DP (default probability), EAD is

We define the loss variable L by L = EAD  SEV x L, where L = 1p with E[15] = DP (default probability), EAD is

We define the loss variable L by L = EAD SEV L, where L = 1p with E[15] = DP (default probability), EAD is the exposure at default and SEV is the random severity with E[SEV] = LGD (loss fraction given default). (a) Assuming SEV and 1p are independent, show that (i) var(1p) = DP(1 DP); (ii) var (SEV1p) = var(SEV) DP + LGD DP(1 - DP). Hint var (X) = E[X] - E[X]. (b) Suppose 1p and 1p are correlated, show that where pi = P[1D = 1|1D = 1] = P + P[1D, 1], i = 1,2. = cov(1D, 1D) P1

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ai Var1p E1p2 E1p2 by the definition of variance E1 E12 since 1p ... View full answer

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