Question: We have learned that, ? b a r ( A ) = AuarrA, A B = ( A u a r r B ) u

We have learned that,
?bar(A)=AuarrA,
AB=(AuarrB)uarr(AuarrB),
A+B=(AuarrA)uarr(BuarrB),
Now, using the above expressions, show that,
(AuarrA)uarr(((AuarrB)uarr(AuarrB))uarr((AuarrB)uarr(AuarrB)))=A,
We have learned that, ? b a r ( A ) = AuarrA, A B

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