We know the standard error of a mean (SEM) equals the standarddeviation (SD) divided by the square root of the number of data(n). Define your own function that can be used to calculate SEMagain and again in the same R session. Which can be the code?

Group of answer choices

SEM<-function({SD/sqrt(n)})

SEM<-{SD/ sqrt(n)}

SEM<-function(SD/sqrt(n))

SEM<-SD/sqrt(n)

SEM<-function(SD,n){SD/sqrt(n)}

Question 7

The successful number is 976, and the total experiment number is7963, at confidence level 90%, what arethe CIs you get by using the Modified Wald Method and the ExactMethod, respectively?

Group of answer choices

[0.1165621, 0.1283369] and [0.1166486, 0.1287416]

[0.1167091, 0.1288037] and [0.1166486, 0.1283413]

[0.1167091, 0.1288037] and [0.1165621, 0.1287769]

[0.1166486, 0.1287416] and [0.06024450, 0.06187106]

Question 8

For questions 8-11, a data file named as“MickeyMouse.csv” looks like:

If you want to read “MickeyMouse.csv” into an object, which ofthe following could be your R command?

Group of answer choices

M6M<-read.table(“MickeyMouse.csv”)

m6<-read.csv(“MickeyMouse”)

6M <-read.csv(“MickeyMouse.csv”)

M6<-read.csv(“MickeyMouse.csv”)

mM6<-read.csv(MickeyMouse.csv)

Question 9

For questions 8-11, a data file named as“MickeyMouse.csv” looks like:

After you read “MickeyMouse.csv” into an object “MM”, if youonly want to select the highlighted data and put the selected datainto object “Smart”, which of the following commands should youtype?

Group of answer choices

Smart<-data.frame(MM[4,2:4],[5,8:10])

Smart<-data.frame(MM[4,2:4],MM[5,8:10])

Smart<-data.frame(MM[4,],MM[5,])

Smart<-MM[4,2:4],MM[5,8:10]

Smart<-data.frame[MM(4,2:4),MM(5,8:10)]

Question 10

For questions 8-11, a data file named as“MickeyMouse.csv” looks like:

For the data being defined in “Smart” in Question 9, what is theCI of the mean of at 99%?

Group of answer choices

[0.940966, 15.358533]

[-8.332323, 28.339953]

[-2.479866, 11.956533]

[0.333333, 11.133233]

[-0.330966, 11.065533]

Question 11

For questions 8-11, a data file named as“MickeyMouse.csv” looks like:

If you typed B<-MM[,6], then

Group of answer choices

C<-data.frame(MM[11,6]) would select the same data values

B selected all the columns in MM

B contains all the data values from row 6 of MM

B contains only 1 number. And this number is from row 6 ofMM.

C<-data.frame(MM[1:11,6]) would select the same datavalues

Answer rating: 100% (QA)

The detailed answer for the above question is provided below Question 1 The correct answer is B The pvalue is the probability ofobtaining the observed ... View the full answer