Question: We now consider C as a function of . We use again 0 = 3 , c = 2 and y ( 0 ) =

We now consider C as a function of . We use again 0=3,c=2 and y(0)=y'(0)=0.
The previous problem determined C for a specific value of . Here we consider a range
of values for and determine numerically the corresponding amplitude C. We then plot
the result as a function of , together with the theoretical amplitude from (3). The plot
is shown in Figure 2. You may need the following MATLAB program.
LAB06ex2
clear all; %this deletes all variables
omega0=3;c=2;
OMEGA =1:0.01:4;
OMEGA));
Ctheory OMEGA));
t0=0;y0=0;v0=0;Y0=[y0;v0];tf=40;t1=13;
for k=1: length (OMEGA)
omega = OMEGA (k);
param omega0, c,omega];
, param

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