We want to compute the integral / (4x2 + 3x + 3 ) edx using two (and only two) integration by parts. This means that you have to make a good choice of f and g' for your two integration by parts. For the first intagration by parts, you should choose [f(x), g'(x)] = Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer, in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get ( 42 2 + 3x + 3) e20 du = G(x) - H(x)da, where G(x) = and H(x) = Now, to integrate H (x) da, we need to use the method of integration by parts a second time with [f(z), g' (z)] = Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer, in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get H(x)da = BE +C (Don't add the constant of integration C since we have done it for you.) We have then found that (42 2 + 3x +3) 2 da =