We want to compute the integral (42 2 + 2a + 4) 20 dac using two (and only two) integration by parts. This means that you have to make a good choice of f and g' for your two integration by parts. For the first intagration by parts, you should choose [f (2), g'(20 ) ] = Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer; in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get ( 42 2 + 2x + 4) 2"' do = G(x) - /H(x)da , where G(ac) = and H(aC) = Now, to integrate / H (a ) dac, we need to use the method of integration by he { zx (er)de , wer parts a second time with If (ac), g'(20 ) ] = Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer; in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get H(x) dx = +C (Don't add the constant of integration C since we have done it for you.) We have then found that (4x2 + 2a + 4 2d do =