What am I missing here? I only got 50% score from this one.

(1 point) (a) Check the local linearity of f(x, y) = ey cos(x) near x = 1.5, y = -1 by filling in the following table of values of f for x = 1.4, 1.5, 1.6 and y = -1.1, - 1, - 0.9. Express values of f with 4 digits after the decimal point. X = 1.4 1.5 1.6 y = -1.1 e^(-1.1)cos( e^(-1.1)cos e^(-1.1)cos Y = -1 e^(-1)cos(1. e^(-1)cos(1. e^(-1)cos(1. y = -0.9 e^(-0.9)cos e^(-0.9)cos e^(-0.9)cos (b) Next, fill in the table for the values x = 1.49, 1.5, 1.51 and y = -1.01, -1, 0.99, again showing 4 digits after the decimal point. X = 1.49 1.5 1.51 y = -1.01 e^(-1.01)cos e^(-1.01)cos e^(-1.01)cos y = -1 e^(-1)cos(1. e^(-1)cos(1. e^(-1) cos(1. y = -0.99 e^(-0.99)cos e^(-0.99)cos e^(-0.99)cos Notice if the two tables look nearly linear, and whether the second looks more linear than the first (in particular, think about how you would decide if they were linear, or if the one were more closely linear than the other). = (c) Give the local linearization of f(x,y) ey cos(x) at (1.5, -1): Using the second of your tables: f(x, y) = ^(-1)cos(1.5)-e^(-1)sin(1.5)(x-1.5)+e^(-1)cos(1.5)(y+1) Using the fact that fz(x,y) = -ey sin(x) and fy(x, y) = ecos(x): f(x,y) ^ e^(-1)cos(1.5)-e^(-1)sin(1.5)(x-1.5)+e^(-1)cos(1.5)(y+1) Results for this submission Entered Answer Preview Result 0.0565771 1.4) 0.0295464 1.1 ce(1.5) inaarest 0.00071998 1.1 ce(1.6) incorreu 0.0625274 come 0.0280223 cus(1.5) Carrer -0.0107410 c-cos(16) irrorest -18 (1.4) met 0.0267503 t Cue(1.5) inaarest -0.0118710 COG(1.8) incorreo -1.DL Cos(1.49) came 0.0257838 e lM cos(1.5) incareul 0.0221295 cos(1.51) incorect 0.029001 CH(1.40) careet 0.0260228 c-cosi 1.5) curred 0.0223519 -1.51) incor 0.00 0.0299094 cus(1.19 carrer 0.0262843 -"cos(1.5) /.1 COS(1.51) incar [e"-17*cos(1.5)-ef-111'cir(1.5)*(x-1.5)+(e"-111'coo:1.51*(x+1) eco(1.5) - feln(1.5) - 1.5) - 1 cos(1.5)(y-1) incarreal [11]'cs:1.5)-9-11 sin(1.5)DX-1.5)(-1]'cos 1.5,"ly+1; c-c1.5) - sin(1.5)(: 1.51 .-'cs(1.5)(1) correct At least one of the answers above is NOT correct (1 point) (a) Check the local linearity of f(x, y) = ey cos(x) near x = 1.5, y = -1 by filling in the following table of values of f for x = 1.4, 1.5, 1.6 and y = -1.1, - 1, - 0.9. Express values of f with 4 digits after the decimal point. X = 1.4 1.5 1.6 y = -1.1 e^(-1.1)cos( e^(-1.1)cos e^(-1.1)cos Y = -1 e^(-1)cos(1. e^(-1)cos(1. e^(-1)cos(1. y = -0.9 e^(-0.9)cos e^(-0.9)cos e^(-0.9)cos (b) Next, fill in the table for the values x = 1.49, 1.5, 1.51 and y = -1.01, -1, 0.99, again showing 4 digits after the decimal point. X = 1.49 1.5 1.51 y = -1.01 e^(-1.01)cos e^(-1.01)cos e^(-1.01)cos y = -1 e^(-1)cos(1. e^(-1)cos(1. e^(-1) cos(1. y = -0.99 e^(-0.99)cos e^(-0.99)cos e^(-0.99)cos Notice if the two tables look nearly linear, and whether the second looks more linear than the first (in particular, think about how you would decide if they were linear, or if the one were more closely linear than the other). = (c) Give the local linearization of f(x,y) ey cos(x) at (1.5, -1): Using the second of your tables: f(x, y) = ^(-1)cos(1.5)-e^(-1)sin(1.5)(x-1.5)+e^(-1)cos(1.5)(y+1) Using the fact that fz(x,y) = -ey sin(x) and fy(x, y) = ecos(x): f(x,y) ^ e^(-1)cos(1.5)-e^(-1)sin(1.5)(x-1.5)+e^(-1)cos(1.5)(y+1) Results for this submission Entered Answer Preview Result 0.0565771 1.4) 0.0295464 1.1 ce(1.5) inaarest 0.00071998 1.1 ce(1.6) incorreu 0.0625274 come 0.0280223 cus(1.5) Carrer -0.0107410 c-cos(16) irrorest -18 (1.4) met 0.0267503 t Cue(1.5) inaarest -0.0118710 COG(1.8) incorreo -1.DL Cos(1.49) came 0.0257838 e lM cos(1.5) incareul 0.0221295 cos(1.51) incorect 0.029001 CH(1.40) careet 0.0260228 c-cosi 1.5) curred 0.0223519 -1.51) incor 0.00 0.0299094 cus(1.19 carrer 0.0262843 -"cos(1.5) /.1 COS(1.51) incar [e"-17*cos(1.5)-ef-111'cir(1.5)*(x-1.5)+(e"-111'coo:1.51*(x+1) eco(1.5) - feln(1.5) - 1.5) - 1 cos(1.5)(y-1) incarreal [11]'cs:1.5)-9-11 sin(1.5)DX-1.5)(-1]'cos 1.5,"ly+1; c-c1.5) - sin(1.5)(: 1.51 .-'cs(1.5)(1) correct At least one of the answers above is NOT correct