What does the below do? #include #include int main(void) { char fnameArray[50] [50]; int i; for...

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What does the below do? #include <stdio.h> #include <string.h> int main(void) { char fnameArray[50] [50]; int i; for (i = 0; i < 5; i++) { scanf("%s", fnameArray[i]); } for (i = 0; i < 5; i++) { } printf("\n%s\n", fnameArray[i]); } return 0; What does the below do? #include <stdio.h> #include <string.h> int main(void) { char fnameArray[50] [50]; int i; for (i = 0; i < 5; i++) { scanf("%s", fnameArray[i]); } for (i = 0; i < 5; i++) { } printf("\n%s\n", fnameArray[i]); } return 0;

Answer rating: 100% (QA)

Answer there is a syntax error in the c... View the full answer