Question: what does this mean However, consider the functions 1 B = (w z)m+1 1 h = - = (w2)H! g w has a 0 of

what does this mean

what does this mean However, consider the
However, consider the functions 1 B = (w z)m+1 1 h = - = (w2)H! g w has a 0 of order m+ 1 at z = a, and so h has a pole of order m + 1 at z = a

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