What is the force $($in N$)$ on Charge $1$ due to Charge $2?$

N

Next, leave Charge $1$ at $10$C and adjust Charge $2$ to $+5$C$.$ There should now be an attractive force of $280\mathrm{.}861$ N observed between them. If Charge $1$ stays at the $0$ cm mark, where could you place Charge $2$ in order to quadruple the magnitude of the electric force between the charges? Use the simulation to check your prediction.

the $1$ cm mark the $2$ cm mark $$ the $6$ cm mark

Now, hit the reset button in the bottom right$-$hand corner of the screen. It looks like the following.

A circular arrow pointing in the counter$-$clockwise direction.

Observe the arrangement where

q$1=4$C

and

q$2=+8$C$.$

Charge

q$1$

is at $4$ cm$,$

q$2$

is at $7$ cm$.$ The force on

q$1$

by

q$2$

is $319\mathrm{.}557$ N to the right, and the force on

q$2$

by

q$1$

is $319\mathrm{.}557$ N to the left. Which of the following changes would result in the force on Charge $2$ by Charge $1$ being reduced to $14$ of the original value?

Moving q$1$ to the $2$ cm mark and leaving q$2$ where it is$.$ Moving q$1$ to the $2$ cm mark and moving q$2$ to the $8$ cm mark $$ Moving q$2$ to the $8$ cm mark and leaving q$1$ where it is$.$ Moving q$1$ to the $0$ cm mark and moving q$2$ to the $10$ cm mark.