What is the work done by that force for the duration of the animation $($note that the displacement and force are in opposite directions, so this is negative work$)?$ Wright$=\_\_\_\_\_\_\_$ k$.$ What is the net work done, then, during the duration of the animation on the water in the middle region? i$.$ This really refers to the net work done to move the same volume of water that is in either dark blue region from the bottom to the top. Wnet$=\_\_\_\_\_\_\_$ l$.$ Calculate the difference in kinetic energy of the dark blue regions. Note that since the volume is the same, the mass is the same. $($The density of water is $1000$ kg$/$m$3.)$ i$.$ This is the difference in kinetic energy between a dark blue volume of water at the low left region and the kinetic energy of the same mass when it is up on the right. $$KEright$-$left$=\_\_\_\_\_\_\_$ m$.$ Calculate the difference in potential energy of the center of mass of the dark blue regions. Does the net work equal the change in kinetic energy plus the change in potential energy? i$.$ Again this change is really the difference between the right and left dark blue masses of water. $$PEright$-$left$=\_\_\_\_\_\_\_$