What is wrong in the following code?

double$*p1=$ new double;

double$*p2=p1$;

$*p2=5\mathrm{.}4$;

delete $p1$;

cout endl;

p $1$ and p $2$ point to the same data, but it was destroyed using delete p $1.$ So you cannot access it later using $*$p$2.$

p$1$ got deleted

p $1$ got deleted and p$2$ got deleted

None of the answer choices are correct

p$1$ does not have a value