What will be the values of the array 'a' after the function executes? You must trace...

 

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What will be the values of the array 'a' after the function executes? You must trace the algorithm carefully outlining all your steps void Mystery() { int hold; int[] a = {62,4,10, 33,1,6,2}; for(int i e; i < a.length-1; i++) { - for(int j = e;j< a.length-1; j++) { if( a[j] <á [j+1]) { %3D %3D hold = a[j]; a[j] = a[j+1]; a[j+1] = hold; } B2. [10 marks] What would be the value of 'mystery_num' after the following block of code executes if number=53468. Trace the algorithm carefully outlining all your steps also showing how each variable changes. int number, mystery_num = 0, digit; while(number > 0) { mystery_num = mystery_num * 10; digit = number % 10; digit = (digit + 7) % 10; mystery_num number = number / 10; %3D mystery_num + digit; } What will be the values of the array 'a' after the function executes? You must trace the algorithm carefully outlining all your steps void Mystery() { int hold; int[] a = {62,4,10, 33,1,6,2}; for(int i e; i < a.length-1; i++) { - for(int j = e;j< a.length-1; j++) { if( a[j] <á [j+1]) { %3D %3D hold = a[j]; a[j] = a[j+1]; a[j+1] = hold; } B2. [10 marks] What would be the value of 'mystery_num' after the following block of code executes if number=53468. Trace the algorithm carefully outlining all your steps also showing how each variable changes. int number, mystery_num = 0, digit; while(number > 0) { mystery_num = mystery_num * 10; digit = number % 10; digit = (digit + 7) % 10; mystery_num number = number / 10; %3D mystery_num + digit; }

Answer rating: 100% (QA)

1 a 62 4 10 33 1 6 2 for i 0 j 0 a j 62 a j 1 4 so ... View the full answer