Question: What would be the IEEE 754 single precision floating point representation of n = -76543210.9876543210 1234 times 10^18? For explanation, I want you to document

What would be the IEEE 754 single precision floating point representation of n = -76543210.9876543210 1234 times 10^18? For explanation, I want you to document the steps your perform, in this order: (1) What is n in decimal fixed point form (ddd.ddddd); (2) What is n in binary fixed point form (bbb.bbbb), storing the first 25 bits following the binary point; (3) What is the normalized binary number, written in the form 1.bbbbb...bbb times 2^e, storing 25 bits following the binary point? (4) What are the 23 mantissa bits, after the bits in bit positions -24, -25, ... are eliminated using the round to nearest, ties to even mode; exclude the 1. part which is not stored; (5) What is the biased exponent in decimal and in binary? (6) Write the 32-bits of the number in the order: s e m; and (7) Write the final answer as an 8-hexdigit number. What decimal floating point number does this big-endian IEEE 754 single precision number represent: n = 0x6C84_3175? For explanation, I want you to document the steps you perform, in this order: (1) What is n in binary; (2) What is the value of the sign bit; What does this value signify about the final number; (3) What are the binary and decimal values of the biased exponent; (4) What is the binary value of the mantissa, with the 1. part preceding the binary point? (5) What is the decimal value of the unbiased exponent; (6) What is the decimal value of the mantissa, with the leading 1. part? (7) What is the final decimal real number, written in the form [-] d.ddddddddd dddddd times 10^e where d represents a decimal digit 0-9 and there is an optional leading negative sign. Write exactly 15 digits after the decimal point (even if they are 0's) and round the final 15^th digit up or down as required based on the value of the 16^th digit (16^th digit
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