What's the answer for question C

Shown below is the output from a linear model predicting armspan (in cm) from height (in inches) and summary statistics. Assume that the association between armspan and height is linear. Use the output and summary statistics to complete parts a through d. LinReg y = a + bx Standard Mean a = 31.258658017 Deviation b = 2.028138528 Height, x 63.50 3.40 12 =0.747319598 Armspan, y 160.05 7.97 r = 0.864476488 a. Report the regression equation, using the words "Height" and "Armspan," not x and y. O A. Predicted Height = 31.26 + 2.03 Armspan B. Predicted Height = 2.03 + 31.26 Armspan c. Predicted Armspan = 31.26 + 2.03 Height O D. Predicted Armspan = 2.03 + 31.26 Height b. Determine the corresponding values and verify the slope by using the formula Sy b= r-. SX r= 0.864 (Round to three decimal places as needed.) Sy = 7.97 (Round to two decimal places as needed.) Sy = 3.40 (Round to two decimal places as needed.) b = 2.03 (Round to two decimal places as needed.) c. Determine the corresponding values and verify the y-intercept by using the formula a =y - bx. y = (Round to two decimal places as needed.) X = (Round to two decimal places as needed.) a = (Round to two decimal places as needed.) Clear all Check