When a satellite is fired into orbit (from a site north of the equator) it goes into an orbit that takes it alternately north and south of the equator. Its distance from the equator is approximately a cosine function of time. Suppose a satellite is fired into orbit. 9 minutes after it leaves the launch site, it reaches its farthest distance north of the equator, 3800 km. 47 minutes later, it reaches its farthest distance south of the equator, also 3800 km. The satellite completes an orbit once every 94 minutes. Optional: See this animation (will open in a new window) for a visual demonstration of this situation. Let y be the number of kilometers the satellite is north of the equator (south will be negative) Lett be the number of minutes elapsed since the satellite was launched. What is the equation expressing y in terms of t? In the space provided on your worksheet, explain your choice. Why do each of the parameters a, b, and d, make sense with your selection? Select one: O a, y = cos((t +5) + 3800 O b. y = 3800cos(( - 9)) oc. y = 3800cos(( + 9)) Od. y = cos((t 9)) + 3800 Oe. y = 3800cos((1 - 9))