When the distance between a point source of light and a light meter is reduced from $4\mathrm{.}0$ m to $2\mathrm{.}0$ m $,$ the intensity of illumination at the meter will be the original value multiplied by:

$($A$)4$

B$)2$

$\frac{1}{2}$

D$)\frac{1}{4}$

E$)16$