Question: When using fork() to create a new process, it typically creates a lazy copy of the process' address space. What does this mean? a. The
When using fork() to create a new process, it typically creates a "lazy copy" of the process' address space. What does this mean?
a. The new process gets its own separate copy of data from the original process' address space
b. This means the new process gets its own shallow copy of the same data of the original process
c. None of these are correct
d. This means the new process points toward the address space of the old process until data changes, then it gets a new area in memory for the new data
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